5600x^2+140x-150=0

Solution for 5600x^2+140x-150=0 equation:

5600x^2+140x-150=0

a = 5600; b = 140; c = -150;
Δ = b2-4ac
Δ = 1402-4·5600·(-150)
Δ = 3379600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3379600}=\sqrt{400*8449}=\sqrt{400}*\sqrt{8449}=20\sqrt{8449}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-20\sqrt{8449}}{2*5600}=\frac{-140-20\sqrt{8449}}{11200}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+20\sqrt{8449}}{2*5600}=\frac{-140+20\sqrt{8449}}{11200}
$